Question

In ΔJKL, j = 27 cm, k = 82 cm and ∠L=162°. Find the area of ΔJKL, to the nearest square centimeter.

Answer 1

342

Explanation:

see image

Answer 2

`684\:\mathrm{cm^2}`

Explanation:

The area of any triangle is equal to
`A=(1)/(2)\cdot a\cdot b\cdot \sin C`, where
`a` and
`b` are two sides of a triangle and
`C` is the angle between them.

Plugging in given values, we have:

`A=(1)/(2)\cdot 27\cdot 82\cdot \sin 162^(\circ)=\boxed{684\:\mathrm{cm^2}}`