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What are the zeros of the function defined by 2x^2-50

User GSTD
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1 Answer

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Answer:


2x^2 - 50 = 0 \\\\2(x^2 - 25) = 0\\\\(x^2 -5^2 ) = 0\\\\(x-5)(x+5) = 0\\\\x = 5, -5

User Raultm
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