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1 vote
Circle has equation x^2+y^2=36

Radius=6
Centre=(0,0)
The distinct point A(a,root11) and B (b,root11) lie on the circumference of the circle. Work out the length AB

User HRM
by
3.3k points

2 Answers

3 votes

Final answer:

The length AB, we need to calculate the distance between the points A and B AB is 0.

Step-by-step explanation:

To find the length AB, we need to calculate the distance between the points A and B. The coordinates of point A are (a, √11) and the coordinates of point B are (b, √11). Since the points lie on the circumference of the circle with equation x^2 + y^2 = 36, we can substitute the y-coordinate (√11) into the equation to find the x-coordinates:

a^2 + (√11)^2 = 36

b^2 + (√11)^2 = 36

Simplifying these equations, we get:

a^2 + 11 = 36

b^2 + 11 = 36

Subtracting 11 from both sides:

a^2 = 25

b^2 = 25

Taking the square root of both sides to solve for a and b:

a = ±5

b = ±5

Since we're dealing with points on the circumference, we take the positive values for a and b:

a = 5, b = 5

Now we can calculate the distance between the points using the distance formula:

AB = √((b - a)^2 + (√11 - √11)^2)

AB = √((5 - 5)^2 + (0)^2)

AB = √(0 + 0)

AB = √0

AB = 0

Therefore, the length AB is 0.

User Robasaurus
by
3.4k points
5 votes
Answer: AB = 10.2

Step-by-step explanation:

A(5.1, root11)
B(-5.1, root11)

AB = |5.1| + |-5.1| = 5.1 + 5.1 = 10.2
User Paul Fitzgerald
by
3.6k points