Answer:
20.
Explanation:
According to the word problem, Mary had 75 fliers and posted 1/3 of them last week.
![75 *(1)/(3) =(75)/(3)](https://img.qammunity.org/2022/formulas/mathematics/high-school/az6r7qpyq6qoxj69lf6gh8kk9tugb87cbm.png)
![(75)/(3) =25.](https://img.qammunity.org/2022/formulas/mathematics/high-school/42dt0z17n7r3slmup6fdhzqcrny7lu4im7.png)
Therefore, Mary posted 25 of them last week.
![75-25 =50](https://img.qammunity.org/2022/formulas/mathematics/high-school/by4bx2gyqomzqyxlohnwz58vtkp0t4iz4k.png)
Mary has 50 fliers that she has not posted.
Then, this week, Mary posted 3/5 of the remaining fliers.
![50*(3)/(5) =(150)/(5)](https://img.qammunity.org/2022/formulas/mathematics/high-school/o21ezwu72au3jbz4cizbrj05idkyv5lwlv.png)
![(150)/(5) =30.](https://img.qammunity.org/2022/formulas/mathematics/high-school/dkxecp5mthlpulxlcsrhyvl6ipb0f2j9kb.png)
Therefore, Mary posted 30 of the remaining fliers this week.
![50-30=20.](https://img.qammunity.org/2022/formulas/mathematics/high-school/u0qqk0kno5k9yp7vi1s98pu3rz2ucbp60t.png)
Therefore, Mary has 20 fliers that she still has not posted.