Question

Sample A: 300 mL of 1M sodium chloride

Sample B: 145 mL of 1.5 M sodium chloride

Which sample contains the larger density?

Answer 1

sample B contains the larger density

Step-by-step explanation:

Given;

volume of sample A, V = 300 mL = 0.3 L

Molarity of sample A, C = 1 M

volume of sample B, V = 145 mL = 0.145 L

Molarity of sample B, C = 1.5 M

molecular mass of sodium chloride, Nacl = 23 + 35.5 = 58.5 g/mol

Molarity is given as;

`C = (moles \ of \ solute, \ mol)/(liters \ of \ solvent) \\\\Moles \ of \ solute \ for \ sample \ A = 1 * 0.3 = 0.3 \ mol\\\\Moles \ of \ solute \ for \ sample \ B = 1.5 * 0.145 = 0.2175 \ mol`

The reacting mass for sample A = 0.3mol x 58.5 g/mol = 17.55 g

The reacting mass for sample B = 0.2175 mol x 58.5 g/mol = 12.72 g

The density of sample A
`= (mass)/(volume) = (17.55)/(0.3) = 58.5 \ g/L`

The density of sample B
`= (mass)/(volume) = (12.72)/(0.145) = 87.72 \ g/L`

Therefore, sample B contains the larger density