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A rectangle with a length of x+5 has a perimeter of 4x+14 a. Write an equation for the width of a rectangle in terms of x b. Suppose the perimeter of the rectangle is 42 inches. What are the length and width of the rectangle? c. Write the expression for the area of the rectangle in terms of x? d. What is the area of the rectangle when x=7

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Answer:

B : Length is 12, Width is 9

D: Area is 108

Explanation:

Finding x:

Since the Perimeter is 42, subtract 14 from 42 to get 28. Then divide that by 4 to get 7. x = 7. Since x = 7 then 7 + 5 = 12. So the length is 12.

Figuring out the width:

When we find the perimeter we add all the sides, so 12 + 12 = 24 and 42 - 24 = 18. Divide 18 by 2 to get 9 and then add 12 + 12 + 9 + 9 just to check your answer

Since the you know the legnht and width, you now have to multiply them to fine the area. 12 x 9 = 108

User Lance Nanek
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