Question

Suppose sonar on the surface of the sea locates an

object at an angle of depression of 65° and a distance
of 320 feet.
How deep is the object?

Answer 1

9514 1404 393

Answer:

290 ft

Explanation:

The relevant trig relation is ...

Sin = Opposite/Hypotenuse

sin(65°) = d/(320 ft)

d = (320 ft)sin(65°) ≈ 290 ft

The object is about 290 feet deep.