Question

Pls help...

solve for x in the following...pls explain

a)7x+5=3x-1
b)5x+12=3x+14​

Answer 1

1:

`7x +5=3x-1\\7x+5-3x=-1\\7x-3x=-1-5\\4x= -1-5\\4x= -6\\x=-(6)/(4) (en donde ambos se divide entre 4)\\Respuesta / x=-(3)/(2)`

2:

`5x+12=3x + 14\\5x+12-3x=16\\5x-3x=16-12\\2x= 16-12\\2x= 4\\x=4/2\\( se divide entre 2)x= 2`

Answer 2

a) x = -1.5

b) x = 1

Explanation:

For problem a, you can start by subtracting 3x from both sides to gather all the like terms together:

7x + 5 = 3x - 1

-3x -3x

4x + 5 = -1

Next, to get the coefficients on one side, you subtract 5 from both sides:

4x + 5 = -1

-5 -5

4x = -6

Now, you divide by 4 on both sides to isolate x:

x = -6/4 = -1.5 --- > x = -1.5

For problem b, you start by subtracting 3x from both sides(kinda like problem a):

5x + 12 = 3x + 14

-3x -3x

2x + 12 = 14

Next, you can subtract 12 from both sides, isolating the "x term".

2x + 12 = 14

-12 -12

2x = 2

Lastly, you can divide by 2 to get x:

x = 1