Question

A container is filled with helium gas. It has a volume of 2.25 liters and contains 9.00 moles of helium. How many moles of helium could be held in a 1.85 liter container at the same temperature and pressure?

Answer 1

Answer: There are 7.4 moles of helium gas present in a 1.85 liter container at the same temperature and pressure.

Step-by-step explanation:

Given:
`V_(1)` = 2.25 L,
`n_(1)` = 9.0 mol

`V_(2)` = 1.85 L,
`n_(2)` = ?

Formula used to calculate the moles of helium are as follows.

`(V_(1))/(n_(1)) = (V_(2))/(n_(2))\\`

Substitute the values into above formula as follows.

`(V_(1))/(n_(1)) = (V_(2))/(n_(2))\\(2.25 L)/(9.0 mol) = (1.85 L)/(n_(2))\\n_(2) = (1.85 L * 9.0 mol)/(2.25 L)\\= 7.4 mol`

Thus, we can conclude that there are 7.4 moles of helium gas present in a 1.85 liter container at the same temperature and pressure.