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1 Answer

3 votes

Answer:

not balanced, oxygen, not equal

Step-by-step explanation:

Alright, so let's go ahead and balance this equation!

The easiest way to do this is to take out a piece of paper and write down your elements on each side. Let's do it together:

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2NaOH + H_(2) SO_(4)
Na_(2)SO_(4) + H_(2)O

Let's count the number of molecules for each element on both sides. Starting with the left side:


2(NaOH) + H_(2) SO_(4)

The coefficient of 2 in front of NaOH will be distributed to Na, O, and H. The subscripts for H and O only apply to themselves, so S will have only one molecule. Then our molecule counts for the reactant side (the left side) will be:

Na: 2

O: 2+4 = 6

H: 2+2 = 4

S: 1

Now, let's move on to the right side:


Na_(2)SO_(4) + H_(2)O

This side only has subscripts, no coefficients, so that means that any elements that don't have subscripts (S and the second O ) will have a count of one. Knowing this, our molecule count for the product side (right side) is:

Na: 2

O: 4+1 = 5

H: 2

S: 1

Let's compare our counts now:

Left side: Right side:

Na: 2 Na: 2

O: 6 O: 5

H: 4 H: 2

S: 1 S: 1

We can see that our O and H molecule counts are different. So that means it's an unbalanced equation.

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Therefore, your answer will be:

The equation is not balanced because the number of hydrogen atoms and oxygen atoms is not equal in the reactants and in the products.

User Ivanna
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