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If you have 8.5 moles of Al2(SO4)3 how many grams of the compound
do you have?

1 Answer

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Answer:


RFM \: of \: aluminium \: sulphate = (2 * 27) + (32 + (16 * 4)) * 3 \\ = 294 \\ 1 \: mole \: weighs \: 294 \: g \\ 8.5 \: moles \: weigh \: (8.5 * 294) \: g \\ = 2499 \: g

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