Question

A force of 20 N acts on a smaller piston of a hydraulic press with an area of ​​10 dm2. How much force does the liquid act on a larger piston of 120 cm2?​

Answer 1

166.6 N

Step-by-step explanation:

Given that,

Force, F₁ = 20 N

Area, A₁ = 10 dm² = 1000 cm²

We need to find the new force if the area of the larger piston is 120 cm². According to Pascal's law,

`F_1A_1=F_2A_2\\\\F_2=(F_1A_1)/(A_2)\\\\F_2=(20* 1000)/(120)\\\\F_2=166.7\ N`

So, the force on the larger piston is equal to 166.7 N.