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If the temperature (at constant volume) of an ideal gas with 20 K is increased to 60 K, the pressure will be: increased to 3P increased to 40P decreased by 3P decreased by 40P
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If the temperature (at constant volume) of an ideal gas with 20 K is increased to 60 K, the pressure will be:

increased to 3P

increased to 40P

decreased by 3P

decreased by 40P

User Pi Horse
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1 Answer

6 votes

Answer:

it will obviously be decreased by 40p

User Shiffty
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