Question

How many ways can a person choose 3 desserts from a desserts tray 8 desserts​

Answer 1

In combinatorics, this question is a combination question, because combination deals with selection while permutations deal with arrangement.

`nCr = (n!)/((n - r)!r!) \\`

Plugging in our values,

`8C3 = (8!)/((8 - 3)!3!) = (8!)/(5!3!) = (8 * 7 * 6 * 5!)/(5!3!) = (8 * 7 * 6)/(3 * 2) = 56 \\`

That means 3 desserts from a tray of 8 desserts 56 times.