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Calculate the approximate temperature of a 0.50 mol sample of gas at 2.7 atm and a volume of 1.20L

User Azarro
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Answer:

79.0 K

Step-by-step explanation:

Assuming the gas behaves like an ideal gas, we can solve this problem by using the following formula:

  • PV = nRT

Where:

  • P = 2.7 atm
  • V = 1.20 L
  • n = 0.50 mol
  • R = 0.082 atm·L·mol⁻¹·K⁻¹ (it is a constant)
  • T = ?

We input the data:

  • 2.7 atm * 1.20 L = 0.50 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * T

And solve for T:

  • T = 79.0 K
User Sanjay Chaudhry
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