Convert this quadratic to vertex form f(x)=(x-h)^2+k by completing the square. 3x^2-6x+6=0

asked May 18, 2022 13.0k views

1 vote

Convert this quadratic to vertex form f(x)=(x-h)^2+k by completing the square.
3x^2-6x+6=0

by Tim L

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3 votes

$f(x)=3x^2-6x+6\\\\f(x)=3(x^2-2x)+6\\\\f(x)=3(\underbrace{x^2-2x+1}-1)+6\\\\ f(x)=3[(x-1)^2-1]+6\\\\f(x)=3(x-1)^2-3+6\\\\f(x)=3(x-1)^2+3$

Seperman answered May 22, 2022

5.2k points

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