Answer:
x =
![√(14)](https://img.qammunity.org/2022/formulas/mathematics/high-school/c8ysh1niprgdsjpcan36nrae3n2sevh9dn.png)
Explanation:
Using Pythagoras' identity in both tight triangles.
First in the small triangle to find the third side ( hypotenuse ) h
h² = 1² + 1² = 1 + 1 = 2 ( take square root of both sides )
h =
![√(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/iou2g3ap7sultma1yhgppxh5ctlpt7kphm.png)
Now use the identity in the larger right triangle
x² + h² = 4²
x² + (
)² = 16
x² + 2 = 16 ( subtract 2 from both sides )
x² = 14 ( take square root of both sides )
x =
![√(14)](https://img.qammunity.org/2022/formulas/mathematics/high-school/c8ysh1niprgdsjpcan36nrae3n2sevh9dn.png)