164k views
0 votes
On a rectangle with length 100 m, width 50m and 2 vehicles stationed together. Find the time that they meet given that car A travels 5 m/s and leaves 3 seconds before car B, and car B is traveling at 3 m/s in the opposite direction. Can you create a generic equation from the previous scenario

User ThilankaD
by
7.6k points

1 Answer

4 votes

Answer:


T=35.625sec

Step-by-step explanation:

From the question we are told that:

Length
L=100 m

Width
W=50m

Velocity of Car A
V_A=5m/s

Velocity of Car B
V_B=3m/s

Distance traveled by car A before car B moves


d_l=5*3


d_l=15

Therefore total distance traveled at same time interval


D=total\ distance-d_l

Where

Total distance=Perimeter of rectangle


P=2(L+B)


P=2(100+50)


P=300

Therefore


D=total\ distance-d_l


D=300-15\\D=285m

Generally the equation for time taken to meet is mathematically given by


T=(Distance D)/(Relative\ speed V_r)

Where

Relative speed = Speed of car A +Speed of car B


V_r=V_A+V_B


V_r=5+3


V_r=8m/s

Therefore the time taken to meet


T=( D)/( V_r)


T=( 285)/( 8)


T=35.625sec

User Andrew Bocz Jr
by
7.7k points