Question

3. Three people are needed to decorate the room where the surprise party will be held. Brenda, Miguel, Ronnte, ten and Dave volunteer. How many different groups of three can be made using these volunteers? I​

Answer 1

Explanation:

there might be some information missing as the problem definition seems to be cut off.

but from what I can see I understand we have to find how many different groups of 3 people we could make out of 5 people in total.

that means the sequence does not matter, right ?

(Brenda, Miguel, Ronne) would be the same as

(Ronne, Brenda, Miguel).

and we can't pick a person twice or thrice for the same group (otherwise we would not make a group, but simply "pick" lottery tickets, where each ticket can win multiple prices).

if that all is the case, then we need to calculate the combinations of 3 elements out of 5 :

5! / (3! × (5-3)!) = 5! / (3! × 2!) = 5×4/2 = 5×2 = 10

we can make 10 different groups of 3 people out of 5 people.