Question

A container of oxygen with a volume of 60 L is heated from 300 K to 400 k, What is the new volume?

Answer 1

80L

Step-by-step explanation:

V1/T1 = V2/T2

V2 = V1 T2/T1

T1 = 300K

V1 = 60L

T2 = 400K

V2 = ?

V2 = V1 T2/T1

V2 = (60L)(400K) / (300K)

V2 = 80L