Question

A sample of gas at 53.0 oC and 1.19 atm occupies a volume of 2.3 L. What volume would this gas occupy at 107 oC and 0.60 atm?

Answer 1

`V_2=5.32L`

Step-by-step explanation:

Hello there!

In this case, according to the given pressure, temperature and volume, it is possible for us to calculate the final volume via the combined ideal gas law:

`(P_2V_2)/(T_2)=(P_1V_1)/(T_1)`

In such a way, we solve for the final volume, V2, to obtain:

`V_2=(P_1V_1T_2)/(T_1P_2)`

Then, we plug in the given data to obtain:

`V_2=(1.19atm*2.3L*380K)/(326K*0.60atm)\\\\V_2=5.32L`

Regards!