Question

Can someone help me draw this out to visualize it?

A plane is 80 miles south and 35 miles east of an airport the pilot wants to fly directly to the airport what bearing should be taken? Draw a picture.

Answer 1

Solution given:

South distance :base[b]=80milea

East distance :perpendicular [p]=35miles

Now

<S=?

we have

`\tan( \alpha ) = (p)/(b) = (35 )/(80)`

`\alpha = \tan {}^( - 1) ( (7)/(16) )`

`\alpha = 23.629°`=24°

24° bearing should be taken from south airport to East airport.