Question

If 5.60 mol of a substance releases 14.9 kJ when it decomposes, what is ΔH for the process in terms of kJ/mol of reactant?

Answer 1

The correct approach is "-2.67 kJ/mole". A further solution is described below.

Step-by-step explanation:

The given values are:

No. of moles,

= 5.60 mol

Substance releases,

ΔH = 14.9 kJ

Now,

The ΔH in terms of kJ/mol will be:

=
`(\Delta H)/(5.60)`

On putting the given values of ΔH, we get

=
`(-14.9)/(5.60)`

=
`-2.67 \ kJ/mole`