Question

Determine the empirical formula for a compound containing 85.6 g of carbon and 14.4 g of hydrogen. Please show work

Answer 1

Answer:
`C_(1)H_(2)`

Step-by-step explanation:

take gram & convert to mol (using the mm of the element) ,

85.6g C
`(1 mol )/(12.01g)` = 7.12 14.4g H
`(1 mol)/(1.01g)` =14.2 then take the smallest number & divide 7.12/7.12 =1 14.2/7.12= 2. since the numbers are in whole numbers the answer is
`C_(1)H_(2)`.