Question

Question in screenshot

Answer 1

See below

Explanation:

`y = {u}^{ (3)/(2) } \\ \\ \therefore \: (dy)/(du) = (3)/(2) {u}^{ (3)/(2) - 1 } = \boxed{(3)/(2) {u}^{ (1)/(2)} } \\ \\ u = 8x + 3 \\ \\ (du)/(dx) = 8.1 + 0 = \boxed{8}`