Question

A French submarine and a U.S. submarine move toward each other during maneuvers in motionless water in the North Atlantic. The French sub moves at 43.00 km/hkm/h , and the U.S. sub at 64.00 km/hkm/h . The French sub sends out a sonar signal (sound wave in water) at 1000 Hz. Sonar waves travel at 5470 km/hkm/h . What is the signal's frequency as detected by the U.S. sub

Answer 1

`f_(U)= 1019.72hz`

Step-by-step explanation:

From the equation we are told that:

Velocity of French sub
`V_(U)= 43.00km/h`

Velocity of U.S. sub at
`V_(F)|=64.00 km//h`

French Wave Frequency
`F_(F)=1000Hz`

Velocity of wave
`V_(s)=5470 km/h`

Generally the equation for Signal's frequency as detected by the U.S. is mathematically given by

Doppler effect

`f_(U) = ( f_F (vs + v_(U)))/((v_s - v_F) )`

`f_(U)= ( 1000 x ( 5470+64))/((5470-43))`

`f_(U)= 1019.72hz`