Question

In an old Sesame Street skit, Kermit the Frog interviewed a local resident on the planet Koozebane, who measures time in gleeps and distance in glorps. One glorp is defined as the distance a rock will fall from rest in one gleep. How far will a rock fall from rest during the second gleep

Answer 1

four glorps

Step-by-step explanation:

We know :

`$y=v_(0y)t + (1)/(2)a_yt^2$`

`$\Rightarrow -1 \text{glorp} = 0 - (g)/(2) * (1 g\text{ gleep})^2$`

`$\Rightarrow 1 \text{ glorp}= (g)/(2) (1 \text{ gleep})^2$` .............(i)

Now, t' = 2 gleep

`$y=v_(0y)t + (1)/(2)a_yt^2$`

`$=0+ (-g)/(2) (2 \text{ gleep})^2$`

`$=-(4g)/(2)(2 \text{ gleep})^2$`

`$=4\left[(-g)/(2) (\text{gleep})^2\right]$`

= 4 (-1 gleep) (From (i))

So, |y| = 4 glorp