Answer:
y≈1.778 (or y=log(3600)/2 or y=log(6)+1)
Explanation:
10^2y=3600
log(10^2y)=log(3600)
2y=log(36)+log(100)
2y=log(6²)+2
2y=2log(6)+2
2y-2=2log(6)
y-1=log(6)
y=log(6)+1
y≈1.778
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