Question

how many grams of NaCl will be produced from 4.67g of FeCl3 in the following reaction? FeCl3+3NaOH -> Fe(OH)3 + 3NaCl

Answer 1

• 1mol of FeCl_3 produces 3mols of NaCl.

Moles of FeCl3

`\\ \rm\hookrightarrow (4.67)/(162.5)=0.03mol`

Now

• moles of NaCl=0.03(3)=0.09mol

Mass of NaCl

• 0.09(58.5)=5.265g

Answer 2

mass of NaCl: 5.0436 g

Step-by-step explanation:

• balanced equation: FeCl₃+3NaOH -> Fe(OH)₃ + 3NaCl

Given:

• 4.67g of FeCl₃

• FeCl₃ molar mass is 162.5 g

solve for moles of FeCl₃

moles = mass/mr

moles = 4.67/162.5

moles = 0.0287

solve for moles of NaCl using molar ratio

FeCl₃ : 3NaCl

1 : 3

0.0288 : 0.0862

Then find mass:

• molar mass of NaCl is 58.5

mass = moles * Mr

mass = 0.0862 * 58.5

mass = 5.0436 g