Question

The period of a pendulum of length 0.500 m is

14.2 s
7.02 s
1.42 s
0.702 s
0.450 s

Answer 1

C. 1.42 s

Step-by-step explanation:

Givens:

length = 0.5m

gravity = 9.807 m/s

Solve:

T = 2π√(L/g)

T = 2π√(0.5/9.807)

T = 2π√(0.0509)

T = 2π * 0.22579

T = 6.28318 * 0.22579

T = 1.418 ≈ 1.42s