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g determine what frequency is required of a source powering a 100 uf capacitor a 500 ohm resistor and a s50 mH inductor in series do the current is maximized

1 Answer

6 votes

Answer:
71.16\ Hz

Step-by-step explanation:

Given

Capacitance
C=100\ \mu F

Resistance
R=500\ \Omega

Inductance
L=50\ mH

In LCR circuit, current is maximum at resonance frequency i.e.


X_L=X_C\ \text{and}\ \omega_o=(1)/(√(LC))

Insert the values


\Rightarrow \omega_o=\frac{1}{\sqrt{50* 10^(-3)* 100* 10^(-6)}}\\\\\Rightarrow \omega_o=(1)/(√(5)* 10^(-3))\\\\\Rightarrow \omega_o=0.447* 10^(3)

Also, frequency is given by


\Rightarrow 2\pi f=\omega_o\\\\\Rightarrow f=(\omega_o)/(2\pi)


\Rightarrow f=(1)/(2\pi)* 0.447* 10^3\\\\\Rightarrow f=71.16\ Hz

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