Question

Special Right Trianglws

Could someone explain how to solve for each step and explain how you got there?

Answer 1

x =
`2\sqrt7`

y =
`2\sqrt7`

Explanation:

Hello!

This is a right isosceles triangle (45°-45°-90°). You can solve for the missing angle by simply subtracting 45° and 90° from 180° (sum of angles in a triangle equals 180°)

Since the triangle is isosceles, x and y are congruent because they are the legs opposite to the congruent angles.

In a right isosceles triangle, the hypotenuse is always the measure of one leg multiplied by
`\sqrt2`.

So, let's use leg y,
`y\sqrt2 = 2√(14)`

Solve for y:

`y\sqrt2 = 2√(14)\\\\y = $(2√(14))/(\sqrt2)$\\\\y = 2\sqrt7`

y =
`2\sqrt7`, which means that x is also
`2\sqrt7`