Question

A weather balloon has a volume of 105L at 0.97 atm when the temperature is 318K. What is the volume

at 293K and 1.05 atm?

Answer 1

89 L

Step-by-step explanation:

Step 1: Given data

• Initial pressure (P₁): 0.97 atm

• Initial volume (V₁): 105 L

• Initial temperature (T₁): 318 K

• Final pressure (P₂): 1.05 atm

• Final volume (V₂): ?

• Final temperature (T₂): 293 K

Step 2: Calculate the final volume of the weather balloon

If we assume that the gas inside the balloon behaves as an ideal gas, we can calculate the final volume of the gas using the combined gas law.

P₁ × V₁ / T₁ = P₂ × V₂ / T₂

V₂ = P₁ × V₁ × T₂ / T₁ × P₂

V₂ = 0.97 atm × 105 L × 293 K / 318 K × 1.05 atm = 89 L