Answer:
95% confidence interval for the proportion of days that IBM stock increases.
(0.45814 , 0.58146)
Explanation:
Step:1
Given that a stock market analyst notices that in a certain year, the price of IBM stock increased on 131 out of 252 trading days.
Given that the sample proportion

Level of significance = 0.05
Z₀.₀₅ = 1.96
Step:2
95% confidence interval for the proportion of days that IBM stock increases.


(0.5198 - 0.06166 , 0.5198+0.06166)
(0.45814 , 0.58146)
Final answer:-
95% confidence interval for the proportion of days that IBM stock increases.
(0.45814 , 0.58146)