418,521 views
10 votes
10 votes
I need help can you help me???

I need help can you help me???-example-1
I need help can you help me???-example-1
I need help can you help me???-example-2
User Ravi Singh
by
2.9k points

2 Answers

13 votes
13 votes

A.

Answer:

~44.65 ft

Explanation:

a = 25

b = 37

c = ?

c^2 = a^2 + b^2

So,

c = √a^2+b^2

c = √(25)^2+(37)^2

c = 44.6542271235 ft

the player is 44.65 ft from the hoop

B.

Answer:

50 ft

Explanation:

a = 40

b = 30

c = ?

c = √(40)^2+(30^2

c = √1600+900

c = √2500

c = 50 ft

User Danny Staple
by
3.3k points
18 votes
18 votes

Answer:

1. about 7.87 feet away

2. About 8.37 yds

Explanation:

1. a^2+b^2=c^2

so 25+37= C^2

= 62

Square root of 62 = 7.87400787401

(About 7.87 ft away)

2. 40+30 = C^2

Square root of 70 = 8.36660026534

About 8.37

User Imnotanelephant
by
2.7k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.