Question

Hi i have homework can you help me

Answer 1

Step-by-step explanation:

The particle will be at rest when its velocity
`v(t)` is equal to zero. Recall that the velocity is simply the derivative of the position
`x(t)` with respect to time:

`v(t) = (dx)/(dt)`

Since
`x(t) = t^2 - 2t + 2`

then

`v(t) = (d)/(dt)(t^2 - 2t + 2) = 2t - 2 = 0`

Solving for t, we find that the particle will be at rest at

`t = 1\:\text{s}`