47.1k views
5 votes
A tortoise crawling at a rate of 0.1 mi/h passes a resting hare. The hare wants to rest another 30 min

before chasing the tortoise at the rate of 5 mi/h. How many feet must the hare run to catch the tortoise?

User Lyric
by
4.4k points

1 Answer

3 votes

Answer:

The rabbit will run 264feet to get to the tortoise

Explanation:

To solve this problem perfectly, we need to take note of the units and conversions involved.

The speed of the tortoise is 0.1 mi/hr

The speed of the hare is 5mi/hr

If the hare rests for another 30 minutes before he starts running the race, We are to get the distance covered by the tortoise under this 30 minutes.

The tortoise runs 0.1 miles in 1 hour

The tortoise will run x miles in 0.5 hours.

x = 0.5 X 0.1 = 0.05 miles.

Therefore, the distance covered by the Tortoise within 30 minutes is 0.05 miles.

The hare will have to run for 0.05 miles before he can catch up to the tortoise.

It is now unit conversion comes into play. We are converting the 0.05 miles to feet so we can get our final answer.

The answer in feet is 264 feet.

Therefore, the rabbit will run 264feet to get to the tortoise

User David Wartell
by
5.2k points