Question

PLEASE HELP ME PLEASEE !

Answer 1

`\sigma = 0.831` --- Standard deviation

`Mode = 10`

Explanation:

Given

`x = 9,8,10,9,8,10,9,10,8,10`

Solving (a): The population standard deviation

First, we calculate the mean

`\bar x = (\sum x)/(n)`

So, we have:

`\bar x = (9+8+10+9+8+10+9+10+8+10)/(10)`

`\bar x = (91)/(10)`

`\bar x = 9.1`

The standard deviation is:

`\sigma = \sqrt{(1)/(n)\sum (x - \bar x)^2}`

So, we have:

`\sigma = \sqrt{(1)/(10)*[(9 - 9.1)^2+.................+(10- 9.1)^2]}`

`\sigma = \sqrt{(1)/(10)*6.9}`

`\sigma = √(0.69)`

`\sigma = 0.831`

The mode is:

`Mode = 10`

10 has the highest frequency of 4