214,430 views
44 votes
44 votes
I don't know how to solve this problem.

I don't know how to solve this problem.-example-1
User Faquan
by
2.7k points

1 Answer

23 votes
23 votes

Length of the rectangular photo = 22 inches

Width of the rectangular photo = 20 inches

Since, width of the frame outside the photo = x inches

Therefore, increase in length and width of the photo with frame = (x + x)

= 2x inches

Length of the photo with frame = (22 + 2x) inches

Width of the photo with frame = (20 + 2x) inches

Combined Area of the photo in the frame = Length × Width

= (22 + 2x)(20 + 2x)

= 22(20 + 2x) + 2x(20 + 2x)

= 440 + 44x + 40x + 4x²

= 4x² + 84x + 440

Therefore, polynomial representing the combined area of the photo in the frame will be (4x² + 84x + 440) square inches.

If width of the frame = 4 inches

Combined area of the photo = 4(4)² + 84(4) + 440

= 840 square inches

User Omari Celestine
by
2.7k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.