Question

Evaluate h(x)=-2x+9 when x=-2,0, and 5 .

h(-2)=

h(0)=

h(5)=

Answer 1

Explanation:

Substitute the value in the parentheses into x.

When x = -2;

`h( - 2) = - 2( - 2) + 9`

`h( - 2) = 4 + 9`

`h( - 2) = 13`

When x = 0;

`h(0) = - 2(0) + 9`

`h(0) = 0 +9`

`h(0) = 9`

When x = 5:

`h(5) = - 2(5) + 9`

`h(5) = - 10 + 9`

`h(5) = - 1`