Evaluate h(x)=-2x+9 when x=-2,0, and 5 . h(-2)= h(0)= h(5)=

asked Jul 9, 2023 2.9k views

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Evaluate h(x)=-2x+9 when x=-2,0, and 5 .

h(-2)=

h(0)=

h(5)=

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3 votes

Explanation:

Substitute the value in the parentheses into x.

When x = -2;

h( - 2) = - 2( - 2) + 9

h( - 2) = 4 + 9

h( - 2) = 13

When x = 0;

h(0) = - 2(0) + 9

h(0) = 0 +9

h(0) = 9

When x = 5:

h(5) = - 2(5) + 9

h(5) = - 10 + 9

h(5) = - 1

Gere answered Jul 13, 2023

by Gere

3.8k points

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