Answer:
(4,2) or x=4, y=2
Explanation:
As your question asks, we'll solve the system of equations by substitution, where we'll solve for the value of one variable and than substitute that value into the other equation and solve for the two variables
we're given the system:
2x+4y=16
3x-2y=8
Let's take the first equation:
you can isolate either x or y, but I'll do x for this problem
2x+4y=16
subtract 4y from both sides
2x=-4y+16
divide both sides by 2
x=-2y+8
now take the second equation (3x-2y=8) and substitute -2y+8 as x
3(-2y+8)-2y=8
do the distributive property
-6y+24-2y=8
combine like terms
-8y+24=8
subtract 24 from both sides
-8y=-16
divide by -8
y=2
we found the value of y. However, we also need to find the value of x
above, we said that x=-2y+8; since we found the value of y, we can substitute that value into the equation and find x
so:
x=-2(2)+8
x=-4+8
x=4
the answer is x=4, y=2. If you need it as a coordinate point, it's (4,2)
Hope this helps!