Question

An enzyme with Km = 3x10-4 M was tested with an initial substrate concentration of 10-6 M. Within one minute, 5% of the substrate had reacted. a) What percentage of substrate will have reacted in 5 min? b) If the initial concentration of substrate was 8x10-7 M, what percentage of substrate will have reacted in 5 min? c) Calculate Vmax. d) A concentration of 9x10-7 M, how long will it take for 50% of the substrate to react? e) A 10-6 M concentration, how long will it take for 75% of the substrate to react?

Answer 1

[S] = 0.02 , Km = 1.2 x10^ -4 , rate = dP/dT = product formed per time = 2.7 x 10^ -6 moles /30 = 9 x10^ -8 we know rate = vmas

Step-by-step explanation: