Answer:
C) 5/36
Explanation:
Now, suppose, dice 1 gives 2. Here also, dice 2 can be anything between 1 and 6. But, the sum of both the dices will be 8 only if dice 2 shows 6.
Similarly, now, if dice 1’s face is 3, sum will be 8 only if dice 2’s upper face shows 5.
If dice 1 shows 4, sum = 8 only if dice 2 is 4.
If dice 1 is 5, sum = 8 only if dice 2 is 3.
If dice 1 is 6, sum= 8 only if dice 2 is 2.
Therefore, sum will be 8 only 5 times. But, sample space consists of 36 values ( combination of values of dice 1 and dice 2).
Therefore, probability = 5/36.
Hope it helps.