Question

ABC ia an isosceles triangle AB=AC and angle A=53° the length of side, a=12.5cm. Calculate the altitude of the triangle correct to 2s.f.

Answer 1

area of traingle=1/2(sin130×AB×AC)

85×3=sin130×AB×AB

255=76×AB²

255/76=AB²

√332.88=AB

AB=18.24

AC=18.24

Explanation:

Hope this helps.