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12 votes
12 votes
How many liters of water can be made from 55 grams of oxygen gas and an excess of

hydrogen at STP?

User Hukeping
by
2.9k points

2 Answers

24 votes
24 votes

1 mole of gas at STP = 22.4 L

Reaction:

2H₂(g) + O₂(g) → 2H₂O(l)

mole oxgen as a limiting reactant

mole oxygen: mass : molar mass = 55 g : 32 = 1.719

mole water H₂O based on mole oxygen as a limiting reactant

mole H₂O from reaction coefficient: 2/1 x mole O₂ = 2/1 x 1.719 = 3.438

liters H₂O at STP = 3.438 x 22.4 L = 77.0112 L

User Norcal Johnny
by
3.1k points
13 votes
13 votes

Answer:


55
grames
02*\left(1\ mol\ 02/32\ g\ 02\right)*\left(2\ mol\ H20/1\ mol\ 02\right)*\left(22.4\ L/1\ mol\ H20\right)=77\ L\ HTO\left(g\right)

Step-by-step explanation:

It's about 62 milliliters in liquid form.

I hope this helps you

:)

User Gary Storey
by
2.6k points