Question

The probability distribution for a

random variable x is given in the table.
-5
3
-2
0
2
3
Probability
.17
.13
33
(16
.10
Find the probability that xs-3

Answer 1

There are only two possible outcomes in the table that satisfy x ≤ -3; either x = -5 or x = -3. Then

P(x ≤ -3) = P(x = -5) + P(x = -3) = 0.17 + 0.13 = 0.3