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Circle A has center of (6, 7), and a radius of 4 and circle B has a center of (2, 4), and a radius of 16. What steps will help show that circle A is similar to circle B?

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Answer:

1) Use translation to coincide the center of a circle with the center of the other circle.

2) We construct the respective loci for the circles.

3) Compare each loci by direct inspection (
f(x,y) must be the same and radii must be different but constant) to conclude the similarity of the two circles.

Explanation:

Geometrically speaking, a circle is formed after knowing its center and radius.

1) Use translation to coincide the center of a circle with the center of the other circle. In this case, we translate the center (
C_(A) (x,y) = (6,7)) of the circle A to the location of the center of the circle B (
C_(B)(x,y) = (2,4)):


C_(A') (x,y) = (6,7) + [(2,4) - (6,7)]


C_(A') (x,y) = (2,4)

2) We construct the respective loci for the circles.

By Analytical Geometric, a circle is represented by the following locus:


(x-h)^(2)+(y-k)^(2) = r^(2)

Where:


x, y - Coordinates of a point of the circunference.


h, k - Coordinates of the center of the circle.


r - Radius of the circle.

3) Compare each loci by direct inspection (
f(x,y) must be the same and radii must be different but constant) to conclude the similarity of the two circles.

Then, the circles A' and B are represented by the following loci:

Circle A'


(x-2)^(2) + (y-4)^(2) = 16

Circle B


(x-2)^(2) + (y-4)^(2) = 256

Since both the
f(x,y) component of each circle is the same and radii are different but constant, then we conclude that circle A is similar to circle B.

User Brennan Pope
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