Question

Geometry help needed!

Answer 1

AC Midpoint (2,0)-

CB Midpoint (5,-4)

midlength is 5

Explanation:

midpoint formula
`((x_(1)+x_(2) )/(2) ,(y_(1) +y_(2) )/(2))`

A(2,4) C(2,-4)

`(2+2)/(2) =(4)/(2)=2\\(4-4)/(2) =(0)/(2) =0`

(2,0)

C(2,-4) B(8,-4)

`(8+2)/(2) =(10)/(2) =5`

`(-4-4)/(2) =(-8)/(2) =-4` midpoint is (5,-4)

Distance between the 2 midpoints is the midsegment

(2,0) and (5,-4)

`d=\sqrt{(x_(2)-x_(1))^(2) +(y_(2)-y_(1)) ^(2) }`

`d=\sqrt{(5-2)^(2) +(-4-0)^(2) } \\d=\sqrt{3^(2) +(-4^(2))\\ } \\d=√(x) 9+16\\d=√(25) \\d=5`