Question

Help asap!

three resistors of 20. ohms, 30. ohms, and 60. ohms, respectively, are connected in series with a battery. a current of 2.0 amperes will flow through this circuit when the potential difference of the battery is a. 20.V b. 220 V c. 110 V d. 10.V.

Answer 1

220 V

Step-by-step explanation:

`r_(1) = 20 ohm\\r_(2) = 30ohm\\r_(3) = 60ohm`

As the resistors are connected in series,

`R_(eq) = r_(1) +r_(2) +r_(3)`

= 20 + 30 + 60

= 110 ohms

V = IR

= 2 * 110

= 220 V

Hope it helps